Answer to Question #297995 in Python for satyasrini

Question

Armstrong numbers between two intervals

Write a program to print all the Armstrong numbers in the given range

A to B(including A and B). An N-digit number is an Armstrong number if the number equals the sum of the Nth power of its digits.

Input

The first line has an integer

A. The second line has an integer B.

Output

Print all Armstrong numbers separated by a space.

If there are no Armstrong numbers in the given range, print

-1.

Explanation

For

A = 150 and B = 200

For example, if we take number 153, the sum of the cube of digits

1, 5, 3 is

13 + 53 + 33 = 153.

So, the output should be

153.

Sample Input 1

150

200

Sample Output 1

153

Sample Input 2

1

3

Sample Output 2

1 2 3

important: please tell me how can we print -1 if there is no armstrong number

Answer 1

def findArmstrong(A, B):
	nums = []
	for n in range(A,B+1):
		str_num = str(n)
		l = len(str_num)
		s = 0
		for i in range(l):
			s += int(str_num[i])**l
		if s == n:
			nums.append(s)
	if nums:
		# if the list contains Armstrong numbers
		# then print these numbers
		print(*nums, sep="\n")
	else:
		# if the list is empty then print -1
		print(-1)


A = int(input())
B = int(input())
findArmstrong(A, B)