Answer to Question #295090 in Python for wallcots750

Question

1: Define a function that takes an argument. Call the function. Identify what code is the argument and what code is the parameter

2: Call your function from Example 1 three times with different kinds of arguments: a value, a variable, and an expression. Identify which kind of argument is which. 

3: Create a function with a local variable. Show what happens when you try to use that variable outside the function. Explain the results.

4: Create a function that takes an argument. Give the function parameter a unique name. Show what happens when you try to use that parameter name outside the function. Explain the results.

5: Show what happens when a variable defined outside a function has the same name as a local variable inside a function. Explain what happens to the value of each variable as the program runs.

Answer 1

def function(x): #x is param
    print(x)
    print(x)
    print(x)


t1 = 1
function(9 - 1)
function('rufus')
function(1)
def fun_2():
    loc = 228

# fun_2() if you run this code,
#print(loc)  there will be an error, since the variable is local
def func_3(unical_param):
    print('really unical')


func_3(1000)
#print(unical_param) if you run this code,there will be NameError
t1 = 7
def fun_4(t1):
    print(t1)
#variable inside a function and a variable with the same name outside
fun_4(t1)