Answer to Question #292035 in Python for codingrookie

Question

Write a Python main function that reads in an integer. Then output (on a line by itself) # is Curzon or # is not Curzon. Have the majority complete just can not figure out what to set the if number= to to get it to print out

Answer 1

n = int(input("Enter the number : "))


n1 = 2**n + 1
n2 = 2*n + 1


if(n1 % n2) == 0:
    print("is Curzon")
else:
    print("is not Curzon")