Answer to Question #290231 in Python for pooja

Question

given a square matrix print the sum all diagonal elements of the matrix

sample input :

3

1 2 3

4 5 6

7 8 9

sample output:

25

Answer 1

N = int(input())
matrix = []
for i in range(N):
    matrix.append([int(j) for j in input().split()])
diagonalSum = 0
antiDiagonalSum = 0
for i in range(N):
    diagonalSum += matrix[i][i]
    antiDiagonalSum += matrix[i][N - 1 - i]


if N % 2 != 0:
    antiDiagonalSum -= matrix[N // 2][N // 2]


print(diagonalSum + antiDiagonalSum)