Answer to Question #289529 in Python for bon

Question

import random

number_letter = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten"]

numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

#print(spell)

#print(number_letter[numbers.index(spell)])

score=0

wrong=0

tries = 3

question =0

while question <= 10:

spell: int = random.choice(numbers)

guess = input(f"Spell {spell}:")

right_answer = number_letter[numbers.index(spell)]

if guess == right_answer:

score= score +1

question= question +1

print("You spelled it right!")

else:

tries= tries - 1

print("Incorrect Spelling.",tries,"left")

if tries == 0:

wrong = wrong + 1

print("Number of trial Exceeded")

in this program i need to spell the number if its wrong it will have a 3 tries and if the 3 tries is over it will become wrong answer then the program will continue until the user solve 10 question. please help me

Answer 1

import random




number_letter = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten"]
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]


score = 0
wrong = 0
tries = 3
question = 0


while question < 10:


	spell = random.choice(numbers)
	
	while tries > 0:


		guess = input(f"Spell {spell}: ")
		right_answer = number_letter[numbers.index(spell)]


		if guess.lower() == right_answer.lower():
			score += 1
			print("You spelled it right!")
			question += 1
			break
		else:
			tries -= 1
			print(f"Incorrect Spelling. {tries} left")


	if tries == 0:
		wrong = wrong + 1
		print("Number of trial Exceeded")
	tries = 3