Answer to Question #278300 in Python for tejasri

Question

A super market plans to conduct a surprise cum lucky winner contest in a different way. The super market sells different vegetables and fruits to customers. Write a python program to accept the items purchased by number of customers under each category [Vegetables and Fruits] with their quantity (in kg) and display the total quantity of items sold under each category. Find out the common item(s) in the shopping basket of the customers. The customer, who buys the highest quantity of common item(s), will be the lucky winner and display the lucky winner customer number.

 

Answer 1

# This loop will go on until the budget is integer or float

while True: 


    try:


        bg = float(input("Enter your budget : "))


        # if budget is integer or float it will be stored 


        # temporarily in variable 's'


        s = bg 


    except ValueError:


        print("PRINT NUMBER AS A AMOUNT")


        continue


    else:


        break

 
# dictionary to store product("name"), quantity("quant"), 
# price("price") with empty list as their values

a ={"name":[], "quant":[], "price":[]}

 
# converting dictionary to list for further updation

b = list(a.values())

 
# variable na value of "name" from dictionary 'a'

na = b[0]

 
# variable qu value of "quant" from dictionary 'a'

qu = b[1]

 
# variable pr value of "price" from dictionary 'a'

pr = b[2]

 
# This loop terminates when user select 2.EXIT option when asked
# in try it will ask user for an option as an integer (1 or 2) 
# if correct then proceed else continue asking options

while True:


    try:


        ch = int(input("1.ADD\n2.EXIT\nEnter your choice : "))


    except ValueError:


        print("\nERROR: Choose only digits from the given option")


        continue


    else:


        # check the budget is greater than zero and option selected


        # by user is 1 i.e. to add an item


        if ch == 1 and s>0:       


  

            # input products name                


            pn = input("Enter product name : ") 


            # input quantity of product


            q = input("Enter quantity : ")


            # input price of the product


            p = float(input("Enter price of the product : "))  

 

            if p>s:


                # checks if price is less than budget


                print("\nCAN, T BUT THE PRODUCT") 


                continue

 

            else:


                # checks if product name already in list


                if pn in na:  


                    # find the index of that product


                    ind = na.index(pn)  

 

                    # remove quantity from "quant"  index of the product


                    qu.remove(qu[ind]) 

 

                    # remove price from "price" index of the product


                    pr.remove(pr[ind])  

 

                    # insert new value given by user earlier


                    qu.insert(ind, q)   

 

                    # insert new value given by user earlier


                    pr.insert(ind, p)   

 

                    # subtracting the price from the budget and assign


                    # it to 's' sum(pr) is because pr = [100, 200] if 


                    # budget is 500 then s = bg-sum(pr) = 200


                    # after updating for same product at index 0 let


                    # pr = [200, 200] so s = 100


                    s = bg-sum(pr)   

 

                    print("\namount left", s)


                else:


                    # append value of in "name", "quantity", "price"


                    na.append(pn)  


  

                    # as na = b[0] it will append all the value in the


                    # list eg: "name":["rice"]


                    qu.append(q)   

 

                    # same for quantity and price


                    pr.append(p)    

 

                    # after appending new value the sum in price


                    # as to be calculated


                    s = bg-sum(pr)   

 

                    print("\namount left", s)

 

        # if budget goes zero print "NO BUDGET"


        elif s<= 0: 


            print("\nNO BUDGET") 


        else:


            break

 
# will print amount left in variable 's'

print("\nAmount left : Rs.", s) 

 
# if the amount left equals to any amount in price list

if s in pr: 


    # then printing the name of the product which can buy


    print("\nAmount left can buy you a", na[pr.index(s)])  

 

print("\n\n\nGROCERY LIST")

 
# print final grocery list

for i in range(len(na)): 


    print(na[i], qu[i], pr[i])