Answer to Question #267956 in Python for Sri ram

Question

Rotate Matrix Rings

Given a matrix of order M*N and a value K, write a program to rotate each ring of the matrix clockwise by K elements. If in any ring has less than or equal to K elements, then don’t rotate that ring.

Input

The first line of input will be two space-separated integers, denoting the M and N.

The next M lines will contain N space-separated integers.

The next line will contain an integer, denoting K.

Output

The output should be M*N matrix by rotating the matrix by K elements.

Explanation

Therefore, by rotating each ring in clockwise direction by 3 elements will give (13, 9, 5, 1, 2, 3, 4, 8, 12, 16, 15, 14) and (10, 6, 7, 11). So the output should be

4 8 12 16

3 10 6 15

2 7 11 14

1 5 9 13

Sample Input 1

4 4

1 2 3 4

5 6 7 8

9 10 11 12

13 14 15 16

3

Sample Output 1

13 9 5 1

14 7 11 2

15 6 10 3

16 12 8 4

Sample Input 2

3 4

1 2 3 4

10 11 12 5

9 8 7 6

2

Sample Output 2

9 10 1 2

8 11 12 3

7 6 5 4

give exact output this question

Answer 1

M, N = input().split(' ')
M, N = int(M), int(N)
matrix = []
for _ in range(M):
  row = [int(x) for x in input().split(' ')]
  matrix.append(row)


#Taking an input from the User
K = int(input())



values = matrix[0][:-1] + [x[-1] for x in matrix][:-1] + matrix[-1][::-1][:-1] + [x[0] for x in matrix][::-1][:-1]



values = values[-K:] + values[:-K]
print(values)



output = matrix



idxs = [(0, j) for j in range(N)][:-1] + [(i, N - 1) for i in range(M)][:-1] + [(M - 1, j) for j in range(N)][::-1][:-1] + [(i, 0) for i in range(M)][::-1][:-1]



idx = 0
for i, j in idxs:
  output[i][j] = values[idx]
  idx += 1


#Printing the output
print(output)