Answer to Question #267514 in Python for Will

Question

Create a program that will accept positive or negative number and store it to a list. Accepting input will stop when empty input is encountered. Count and display all positive and negative number input and its index number in the list. Count and display all even and odd positive numbers and its index number. Exclude 0 input.

 

Example:

 

number 1: 78

number 2: 91

number 3: -5

number 4: 0

number 4: 8

number 5: -100

number 6: -2

number 7: 100

number 8:

 

There are 4 positive numbers

All positive numbers: 78 91 8 100

Positive numbers can be found at index number: 0 1 3 6

There are 3 negative numbers

All negative numbers: -5 -100 -2

Negative numbers can be found at index number: 2 4 5

There are 3 positive even numbers

Positive even numbers are: 78 8 100

Positive even numbers can be found at index: 0 3 6

There are 1 positive odd numbers

Positive odd numbers are: 91

Positive odd numbers can be found at index: 1

Answer 1

# Python program to count positive and negative numbers in a List 

  
# list of numbers 

list1 = [-10, -21, -4, -45, -66, 93, 11] 


  

pos_count, neg_count = 0, 0


num = 0


  
# using while loop      

while(num < len(list1)): 


      

    # checking condition 


    if list1[num] >= 0: 


        pos_count += 1


    else: 


        neg_count += 1


      

    # increment num  


    num += 1


      

print("Positive numbers in the list: ", pos_count) 


print("Negative numbers in the list: ", neg_count)