Answer to Question #265532 in Python for Matteo Villamor

Question

if op==1 or op==2 or op==3 or op==4 or op==5 or op==6 :

a = int(input("Enter first number"))

b = int(input("Enter second number"))

dict1 = {1:a+b, 2:a-b, 3:a*b, 4:a/b, 5:a%b, 6:a**b}

print ("The result is : " + str(dict1.get(op)))

elif op==7 or op==8 or op==9 or op==10 or op==11 or op==12 :

a = float(input("Enter the number"))

dict2 = {7:math.fabs(a), 8:math.factorial(a), 9:math.log(a), 10:math.ceil(a), 11:math.floor(a), 12:math.sqrt(a)}

print ("The result is : " + str(dict2.get(op)))

elif op==13 :

print ("Functions Menu")

print ("a. sin")

print ("b. cos")

print ("c. tan")

fun = input("Choose the function :")

a = float(input("Enter the angle in radians :"))

dict3 = {'a':math.sin(a), 'b':math.cos(a), 'c':math.tan(a)}

print ("The result is : " + str(dict3.get(fun)))

Question:

1. In this program, you will create a class and OOP.

Answer 1

import math


op = int(input("Option (1 ... 13): "))


if op == 1 or op == 2 or op == 3 or op == 4 or op == 5 or op == 6:
    a = int(input("Enter first number"))
    b = int(input("Enter second number"))
    dict1 = {1: a+b, 2: a-b, 3: a*b, 4: a/b, 5: a % b, 6: a**b}
    print("The result is : " + str(dict1.get(op)))
elif op == 7 or op == 8 or op == 9 or op == 10 or op == 11 or op == 12:
    a = float(input("Enter the number"))
    dict2 = {7: math.fabs(a), 8: math.factorial(a), 9: math.log(
        a), 10: math.ceil(a), 11: math.floor(a), 12: math.sqrt(a)}
    print("The result is : " + str(dict2.get(op)))
elif op == 13:
    print("Functions Menu")
    print("a. sin")
    print("b. cos")
    print("c. tan")


fun = input("Choose the function :")
a = float(input("Enter the angle in radians :"))
dict3 = {'a': math.sin(a), 'b': math.cos(a), 'c': math.tan(a)}
print("The result is : " + str(dict3.get(fun)))