Answer to Question #262464 in Python for Chiarra

Question

Counting Num

by CodeChum Admin

To give you more of a challenge with a number's digits, let's try counting how many of a certain digit is present on a given number.

Let's start coding!

Instructions:

1. Input two integer values. The first one shall accept any integer from 0-9 and the other one shall take a non-zero positive integer.
2. Using a while loop, count how many of the first integer (0-9) is present in the digits of the second inputted integer and print the result (see sample input and output for example).
3. Tip #1: You have to use your knowledge from the previous problems in looping through the digits of a number: % 10 to get the rightmost digit, while / 10 to remove the rightmost digit. Make sure to solve the previous problems first.

Input

A line containing two integers separated by a space.

2·124218

Output

A line containing an integer.

2

Answer 1

digit, num = map(int, input().split())
count = 0
while num:
    if num % 10 == digit:
        count +=1
    num = num // 10
print(count)