Answer to Question #244378 in Python for Hiruni

Question

Develop a program to read the name, birthday and gender of a person from a file and output the name and ten-digit identity card (NIC) number to another file , each name starting on new line (see

The only input to the program is the name of the file. The output of the programme is the file "output.txt".
rules for NIC number.
The first four digits of the ID card is the birth year.
The next three digits are the number of days to the birth date from January 1st of that year. If the person is a female, 500 is added to that value.
The next three digits are assigned in the order of submission for a particular birth year.
The input file contains the records in the order of submission where each attribute is space separated.
In example , Aruni is the second entry in the year 1990. Therefore the last three digits of the NIC are 002.
Assume there are only 999 entries per year.
Example:
Saman 1990-05-03 M
Aruni 1990-04-06 F

Saman 1990123001




You may use the function,

days_to_birthday(date)

Answer 1

from datetime import datetime
file_name = input()
file1 = open(file_name, 'r')
Lines = file1.readlines()
count = 0
year_prev = 0
NIC_Code = []
f = open("output.txt", "r+")
f.truncate(0)
for line in Lines:
  words = line.split()
  if year_prev==0:
    year_prev= words[1].split("-")[0]
  if year_prev != words[1].split("-")[0]:
    count = 0
  count += 1
  nic = ''
  nic=nic+words[0]
  start_date = str(words[1].split("-")[0])+"-01-01"
  days = ((datetime.strptime(words[1],"%Y-%m-%d") - datetime.strptime(start_date,"%Y-%m-%d")).days)+1
  if words[2]=="F":
    nic=nic+str(days+500)
  else:
    nic=nic+str(days)
  if count<10:
    nic=nic+"00"+str(count)
  elif count>=10 and count<100:
    nic=nic+"0"+str(count)
  else:
    nic=nic+str(count)
  print(nic)
  year_prev = words[1].split("-")[0]
  f.write(words[0]+" "+nic+"\n")
f.close()

Sample Input

task1.txt
Saman123001
Aruni596002

One file "output.txt" will be saved.