Answer to Question #229887 in Python for srikanth

Question

Shaded Diamond Given an integer value N as input,write a program to print a shaded diamond of 2*N -1 rows using an asterisk(*) character as shown below.
Sample Input 1
6
Sample Output 1
     * 
    * * 
   * * * 
  * * * * 
 * * * * * 
* * * * * * 
 *       *
  *     *
   *   *
    * *
     *
Sample Input 2
5
Sample Output 2
    * 
   * * 
  * * * 
 * * * * 
* * * * * 
 *     *
  *   *
   * *
    *
this code not correct output:
N = int(input())
for ​i in range(1, N + 1):
    for j in range(1, N - i + 1):
        print(end = ' ')
    for l in range(1, 2 * i):
        if l == 1 or l == i * 2 - 1:
            print('*', end = '')
        else:
            print('*', end = '')
    print()
for ​i in range(N - 1, 0, -1):
    for j in range(1, N - i + 1):
        print(' ', end = '')
    for l in range(1, 2 * i):
    print()

Answer 1

# the code bolow is as as close to original as possible
N = int(input())
for i in range(1, N + 1):
    for j in range(1, N - i + 1):
        print(end = ' ')
    for l in range(1, i + 1):
        # if l == 1 or l == i * 2 - 1:
        #     print('*', end = '')
        # else:
            print('*', end = ' ')
    print()
for i in range(N - 1, 0, -1):
    for j in range(1, N - i + 1):
        print(' ', end = '')
    print('*', end = '')
    for l in range(1, 2 * i - 2):
        print(' ', end = '')
    if i > 1:
        print('*')