Answer to Question #225611 in Python for kaavya

Question

Roots of a quadratic equation

You are given coefficients a, b and c of a quadratic equation ax² + bx + c = 0. Find the roots r1, r2 of the equation.

Note:

r1 and r2 should be rounded up to 2 decimal places.Input

The first line of input is an integer a. The second line of input is an integer b. The third line of input is an integer c.

Explanation

In the given example, a = 1, b = -5, c = 6. Then the equation is x² - 5x + 6 = 0

r1 = (-b + (b^2 - 4*a*c)^0.5)/2*a

r1 = (5 + (25 - 24))/2

r1 = 3

and

r2 = (-b - (b^2 - 4*a*c)^0.5)/2*a

r2 = (5 - (25 - 24))/2

r2 = 2

So, the output should be

3

2

Sample Input 1

1

-5

6

Sample Output 1

3.0

2.0

Sample Input 2

-1

1

6

Sample Output 2

-2.0

3.0

Answer 1

a, b, c = [int(input()) for _ in range(3)]
if a == 0:
    print(round(-c / b, 2))
else:
    d = b * b - 4 * a * c
    if d < 0:
        print('no roots')
    elif d == 0:
        print(round(-b / 2 / a, 2))
    else:
        print(round((-b - d ** 0.5) / 2 / a, 2))
        print(round((-b + d ** 0.5) / 2 / a, 2))