Question #221432

3-digit Armstrong Number

Write a program to check if a given 3-digit number

X is an Armstrong number or not.Note: A number is an Armstrong number if the number is equal to the sum of the Nth power of its digits.Input

The first line is an integer

X.Output

The output should be a single line containing

True if it satisfies the given conditions, False in all other cases.Explanation

In the given example

X = 371, The number of digits in 371 is 3. So, 33 + 73 + 13 = 371. Hence,

371 is an Armstrong number.So, the output should be

True.

Sample Input 1

371

Sample Output 1

True




Expert's answer

n = input('Enter 3 digit number here: ')
n1 = int(n)
if n1 == int(n[0])**3 + int(n[1])**3 + int(n[2])**3:
    print(True)
else:
    print(False)

Enter 3 digit number here: 371
True
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