Answer to Question #199433 in Python for Narendra

Question

Rotate Matrix Rings

Given a matrix of order M*N and a value K, write a program to rotate each ring of the matrix clockwise by K elements. If in any ring has less than or equal to K elements, then don’t rotate that ring

M, N = input().split()
M, N = int(M), int(N)
matrix = []
for _ in range(M):
	row = [int(x) for x in input().split()]
	matrix.append(row)
K = int(input())
values = matrix[0][:-1] + [x[-1] for x in matrix][:-1] + matrix[-1][::-1][:-1] + [x[0] for x in matrix][::-1][:-1]
values = values[-K:] + values[:-K]
output = matrix
idxs = [(0, j) for j in range(N)][:-1] + [(i, N - 1) for i in range(M)][:-1] + [(M - 1, j) for j in range(N)][::-1][:-1] + [(i, 0) for i in range(M)][::-1][:-1]
idx = 0
for i, j in idxs:
	output[i][j] = values[idx]
	idx += 1
for i in output:
  pass
  print(i)

Input:

4 4

1 2 3 4 

5 6 7 8 

9 10 11 12 

13 14 15 16 

3

Output:

[13, 9, 5, 1]

[14, 6, 7, 2]

[15, 10, 11, 3]

[16, 12, 8, 4]

Here the inner ring is not rotating the given times sir

Answer 1

M, N = input().split()
M, N = int(M), int(N)
matrix = []
for _ in range(M):
	row = [int(x) for x in input().split()]
	matrix.append(row)
K = int(input())


values = []
k = 0
l = 0
while (((N - k) > 0) and ((M - l) > 0)) and ((N - k)*(M-l)) > K:
	for i in range(k,N):
		values.append(matrix[k][i])
	for j in range(l+1,M):
		values.append(matrix[j][N-1])
	for i in range(N-2,k-1,-1):
		values.append(matrix[M-1][i])
	for j in range(M-2,l,-1):
		values.append(matrix[j][k])
	values = values[-K:] + values[:-K]
	c = 0
	for i in range(k,N):
		matrix[k][i] = values[c]
		c += 1
	for j in range(l+1,M):
		matrix[j][N-1] = values[c]
		c += 1
	for i in range(N-2,k-1,-1):
		matrix[M-1][i] = values[c]
		c += 1
	for j in range(M-2,l,-1):
		matrix[j][k] = values[c]
		c += 1		
	values = []
	k += 1
	l += 1
	M -= 1
	N -= 1






for i in matrix:


  print(i)