Answer to Question #199050 in Python for kolsuz

Question

Write a function even_int that consumes an integer and produces "Even" if it is even and

"Odd" otherwise. You should use if and else for the two cases.

Answer 1

def even_int(n):
    if n%2==0:
        print("Even")
    else:
        print("Odd")
        
if __name__ == '__main__':
    even_int(3)