Answer to Question #196635 in Python for FORTUNE AIDOO

Question

CONTINUATION......

alphabet = "abcdefghijklmnopqrstuvwxyz"   

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"] 

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog. 

def histogram(s):

   d = dict()

   for c in s:

     if c not in d:

        d[c] = 1

     else:

        d[c] += 1

   return d 

  Implement has_duplicates by creating a histogram using the histogram function above. Instead, your implementation should use the counts in the histogram to decide if there are any duplicates. 

Write a loop over the strings in the provided test_dups list.

Answer 1

def histogram(s):
   d = dict()
   for c in s:
     if c not in d:
        d[c] = 1
     else:
        d[c] += 1
   has_duplicates(d)
   return d


def has_duplicates(d):
    Flag=0
    k = list(d.keys())
    for r in range(0,len(k)):
        if(d[k[r]]>1): Flag=1
    return(Flag)    
    
alphabet  = "abcdefghijklmnopqrstuvwxyz"   
test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"] 
test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog."] 
test_new  = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog.","zzz"]


x = histogram(alphabet)
y = has_duplicates(x)
if(y==1):    print("\nThe string < %s > has duplicates"%alphabet)
if(y==0):    print("\nThe string < %s > has no duplicates"%alphabet)


x = histogram(test_dups)
y = has_duplicates(x)
if(y==1):    print("\nThe string < %s > has duplicates"%test_dups)
if(y==0):    print("\nThe string < %s > has no duplicates"%test_dups)


x = histogram(test_miss)
y = has_duplicates(x)
if(y==1):    print("\nThe string < %s > has duplicates"%test_miss)
if(y==0):    print("\nThe string < %s > has no duplicates"%test_miss)


x = histogram(test_new)
y = has_duplicates(x)
if(y==1):    print("\nThe string < %s > has duplicates"%test_new)
if(y==0):    print("\nThe string < %s > has no duplicates"%test_new)