Answer to Question #194016 in Python for J NAGAMANI

Question

Number to English Words

Write a program to convert a non-negative integer

N to its English words representation.Input

The input will be a single line containing an integer

N. Note: The input number will not be greater than 10¹⁰.Output

The output should be a single line containing the representation of the English words of number

N. See the sample input and output for the English words of numbers in places.Explanation

For example, if the given number is 123, your code should print the English words representation, which is

One Hundred Twenty Three

Sample Input 1

123

Sample Output 1

One Hundred Twenty Three

Sample Input 2

10005

Sample Output 2

Ten Thousand Five

Answer 1

ones = {0: '', 1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six',
        7: 'Seven', 8: 'Eight', 9: 'Nine', 10: 'Ten', 11: 'Eleven', 12: 'Twelve',
        13: 'Thirteen', 14: 'Fourteen', 15: 'Fifteen', 16: 'Sixteen',
        17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
tens = {2: 'Twenty', 3: 'Thirty', 4: 'Forty', 5: 'Fifty', 6: 'Sixty',
        7: 'Seventy', 8: 'Eighty', 9: 'Ninety'}
illions = {1: 'Thousand', 2: 'Million', 3: 'Billion'}




def convertIntegerIntoWord(i):
    if i == 0:
        return 'zero'
    return getNumberPosition(i)




def getNumberPosition(i):
    if i < 20:
        return ones[i]
    if i < 100:
        return joinWords(tens[i // 10], ones[i % 10])
    if i < 1000:
        return divItems(i, 100, 'Hundred')
    for inumber, iname in illions.items():
        if i < 1000**(inumber + 1):
            break
    return divItems(i, 1000**inumber, iname)




def divItems(position, inumber, iname):
    return joinWords(
        getNumberPosition(position // inumber),iname,getNumberPosition(position % inumber),
    )




def joinWords(*words):
    return ' '.join(filter(bool, words))




number = int(input())
print(convertIntegerIntoWord(number))