Answer to Question #192297 in Python for LEROY

Question

   

def novel_or_knockoff(name, off_brand):

 # novel_or_knockoff() 

  

 # @type: 

 # @rtype: 

 count = 0

 for index in range(0,len(name)):

  if name[index] != off_brand[index]:

   count = count + 1

 if count >= 3:

  return "Novelty"

  

 else:

  return "Knockoff"

# Example: if Playstation [index] != playstation [index] :

     count = count + 1

     if count >= 3:

      return "Novelty"

     else;

      return "Knokoff"

Answer 1

def novel_or_knockoff(name, off_brand):


	count = 0
	for index in range(len(name)):
		if name[index] != off_brand[index]:
			count += 1
		if count = 3:
			return "Novelty"
	return "Knockoff"