Answer to Question #171434 in Python for Paul Carpenter

Question

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

def histogram(s):

d = dict()

for c in s:

if c not in d:

d[c] = 1

else:

d[c] += 1

return d

Part 1

Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

aaa has duplicates

abc has no duplicates

Part 2

Write a loop over the strings in list test_miss and call missing_letters with each string. Print a line for each string listing the missing letters. For example, for the string "aaa", the output should be the following.

aaa is missing letters bcdefghijklmnopqrstuvwxyz

abcdefghijklmnopqrstuvwxyz uses all these letters

Answer 1

# Part 1:
	

	def has_duplicates (str):
	    count = histogram(tuple(str))
	    for key in count:
	        check = count[key]
	        if check > 1:
	            return True
	    return False
	

	for e in test_dups:
	    if has_duplicates(e):
	        print(str(e)+' has duplicates')
	    else: 
	        print(str(e)+' has no duplicates')

# Part 2:
	

	def missing_letters (str):
	    dic_str = histogram(tuple(str))
	    arr = list(alphabet)
	    for letter in dic_str:
	        if letter in alphabet:
	            arr.remove(letter)
	    new_str = "".join(arr)
	    return new_str
	

	for e in test_miss:
	    if missing_letters(e):
	        print(str(e)+' is missing letters '+str(missing_letters(e)))
	    else:
	        print(str(e)+ ' uses all the letters' )