Answer to Question #169567 in Python for Chandra sena reddy

Question

You are given a square matrix A of dimensions NxN. You need to apply the below given 3 operations on the matrix A.

Rotation: It is represented as R S where S is an integer in {90, 180, 270, 360, 450, ...} which denotes the number of degrees to rotate. You need to rotate the matrix A by angle S in the clockwise direction. The angle of rotation(S) will always be in multiples of 90 degrees.

Update: It is represented as U X Y Z. In initial matrix A (as given in input), you need to update the element at row index X and column index Y with value Z.

After the update, all the previous rotation operations have to be applied to the updated initial matrix.

Querying: It is represented as Q K L. You need to print the value at row index K and column index L of the matrix A. Input

The first line contains a single integer N.

Next N lines contain N space-separated integers Aij (i - index of the row, j - index of the column).

Next lines contain various operations on the array. Each operation on each line (Beginning either with R, U or Q).

-1 will represent the end of input.Output

For each Query operation print the element present at row index K and colum index L of the matrix in its current state.Explanation

For Input:

2

1 2

3 4

R 90

Q 0 0

Q 0 1

R 90

Q 0 0

U 0 0 6

Q 1 1

-1

Initial Matrix

1 2

3 4

For R 90, clockwise rotation by 90 degrees, the matrix will become

3 1

4 2

For Q 0 0, print the element at row index 0 and column index 0 of A, which is 3.

For Q 0 1, print the element at row index 0 and column index 1 of A, which is 1.

Again for R 90, clockwise rotation by 90 degrees, the matrix will become

4 3

2 1

For Q 0 0, print the element at row index 0 and column index 0 of A, which is 4.

For U 0 0 6, update the value at row index 0 and column index 1 in the initial matrix to 6. So the updated matrix will be,

6 2

3 4

After updating, we need to rotate the matrix by sum of all rotation angles applied till now(i.e. R 90 and R 90 => 90 + 90 => 180 degrees in clockwise direction).

After rotation the matrix will now become

4 3

2 6

Next for Q 1 1, print the element at row index 1 and column index 1 of A, which is 6.

output

3

1

4

6

Sample Input 1

2

1 2

3 4

R 90

Q 0 0

Q 0 1

R 90

Q 0 0

U 0 0 6

Q 1 1

-1

Sample Output 1

3

1

4

6

Sample Input 2

2

5 6

7 8

R 90

Q 0 1

R 270

Q 1 1

R 180

U 0 0 4

Q 0 0

-1

Sample Output 2

5

8

8

please give me the best solution.

Answer 1

from copy import deepcopy


def rotate90_clockwise(mat):
    return [list(reversed(col)) for col in zip(*mat)]


def rotate(mat, _angle):
    _angle = _angle % 360 // 90
    for _ in range(_angle):
        mat = rotate90_clockwise(mat)
    return mat


def update(mat, rot_list, _args):
    i, j, value = map(int, _args)
    mat[i][j] = str(value)
    mat = rotate(mat, sum(rot_list))
    return mat


def query(mat, _args):
    i, j = map(int, _args)
    print(mat[i][j])


if __name__ == "__main__":
    n = int(input())
    matrix = []
    for _ in range(n):
        matrix.append(
            list(input().split())
        )
    handle = ""
    rotation_list = []
    initial_matrix = deepcopy(matrix)
    while handle != "-1":
        handle, *args = input().split()
        if handle == "R":
            angle = int(args[0])
            rotation_list.append(angle)
            matrix = rotate(matrix, angle)
        elif handle == "U":
            matrix = update(deepcopy(initial_matrix), rotation_list, args)
        elif handle == "Q":
            query(matrix, args)