a=[1, 2, 3, 4, 4, 4, 5, 6, 5, 6]
c=0
for i in range(len(a)):
if a.count(a[i]) == 1:
print('YES', a[i])
c=1
if c == 0:
print('NO')
For example, we have list of digits 1, 2, 3, 4, 4, 4, 5, 6, 5, 6 and c=0
In the loop we check the count of each digit in the list. If it is unique, program output 'YES' and unique digit than c become equal 1. But if there are not unique objects, program output 'NO'
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