Answer to Question #100463 in Python for oladepo

Question

Encapsulate the following Python code in a function named my_sqrt that takes a as a parameter, chooses a starting value for x, and returns an estimate of the square root of a.
while True:
y = (x + a/x) / 2.0
if y == x
break
x = y

Answer 1

def my_sqrt(a):
    x = a
    while True:
        y = (x + a/x) / 2.0
        if y == x:
            break
        x = y
    return y