Question

A microprocessor uses RAM chips of 1×1024 capacity.

How many chips will be required to obtain a memory capacity of 16 𝐾 bytes?

How many chips will be required and how many address lines will be connected to provide a capacity of 1024 bytes?

Answer 1

We are given:

The capacity of the chip is $= (1024 \times 1 ) = 1024$ bits

We have to obtain a memory whose capacity is $16$ K bytes or $(16 \times 1024 \times 8 )$ bits.

Hence:

The number of chips required to obtain a memory capacity of $16$ K bytes are:

$= \dfrac{16 \times 1024 \times 8 }{1024}$

$\, = \color{blue}{128}$

Again:

We have to obtain a memory whose capacity is $1024$ bytes or $(1024 \times 8)$ bits

Hence:

The number of chips required to obtain a memory capacity of $1024$ bytes are:

$= \dfrac{1024 \times 8}{1024}$

$= \color{blue}{ 8}$

Now:

Since $2^{10} = 1024$ so a memory chip capacity of $1024$ bytes connected with $\color{blue}{10}$ address lines.