Question

Decent vehicle is traveling vertical@ 5.5 m/s and has horizontal velocity of 3.5 m/s . What speed and angle is descent path ?

Answer 1

Answer on Question #47780, Physics, Computational Physics

Question:

Decent vehicle is traveling vertical@ 5.5 m/s and has horizontal velocity of 3.5 m/s. What speed and angle is descent path?

Answer:

Total speed equals (using Pythagorean theorem):

$$v = \sqrt {v _ {v} ^ {2} + v _ {h} ^ {2}} \cong 6. 5 \frac {m}{s}$$

where $v_{v}$ is vertical velocity, $v_{h}$ is horizontal velocity.

Angle equals:

$$\tan \alpha = \frac {v _ {v}}{v _ {h}}$$ $$\alpha = \arctan \frac {v _ {v}}{v _ {h}} = 57.5^{\circ}$$

Answer: $6.5\frac{m}{s}, 57.5^{\circ}$

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