// Answer on Question#41055 - Programing - Javapublic class Shift { static int[] shift(int A[], int p, String d) { int temp[] = new int[A.length]; int j = 0; if (d.equals("R")) { for (int i = A.length - p; i < A.length; i++) { temp[j++] = A[i]; } for (int i = 0; i < A.length - p; i++) { temp[j++] = A[i]; } } if (d.equals("L")) { for (int i = p; i < A.length; i++) { temp[j++] = A[i]; } for (int i = 0; i < p; i++) { temp[j++] = A[i]; } } return temp; } public static void main(String args[]) { int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; System.out.println("Original array: "); for (int i = 0; i < arr.length; i++) { System.out.print(arr[i] + " "); } System.out.println("\n"); int out[] = shift(arr, 10, "R"); System.out.println("after p=10 d=R:"); for (int i = 0; i < out.length; i++) { System.out.print(out[i] + " "); } System.out.println(""); int out1[] = shift(arr, 8, "L"); System.out.println("\nafter p=8 d=L:"); for (int i = 0; i < out1.length; i++) { System.out.print(out1[i] + " "); } System.out.println(""); int out2[] = shift(arr, 2, "L"); System.out.println("\nafter p=2 d=L:"); for (int i = 0; i < out2.length; i++) { System.out.print(out2[i] + " "); } System.out.println(""); int out3[] = shift(arr, 4, "R"); System.out.println("\nafter p=4 d=R:"); for (int i = 0; i < out3.length; i++) { System.out.print(out3[i] + " "); } }}
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