Answer to Question #310851 in Java | JSP | JSF for Jay

Question

The value of y is calculated as follows:-

y = 4x3 + 2x 6 when x > 5

y = 3x2 4y + 12 when x < 5

y = 6x 5 when x = 5

Write a program that accepts the value x and then computes the value of y.

Answer 1

public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);

    System.out.println("Input x:");
    int x = scanner.nextInt();
    double y;

    if (x > 5) {
       y = 4 * Math.pow(x, 3) + 2 * Math.pow(x, 6);
    } else if (x < 5) {
        y = 3 * Math.pow(x, 2) + 12;
    } else {
        y = 6 * Math.pow(x, 5);
    }

    System.out.println("y = " + y);
}