Question

Develop a java program to get n numbers as input and find the second duplicate and print the reverse of a number

First line contains the value n and the remaining lines contain the corresponding input

Input:

5

11

24

33

11

24

Output:

42

Note:

If the second duplicate is single digit, print as it is

If there is no second duplicate, print the first duplicate itself

If there is no duplicate, print "No duplicate found

Answer 1

package com.task;

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        Integer cnt = Integer.valueOf(sc.next());
        Integer[] arr = new Integer[cnt];
        for (int i = 0; i < cnt; i++) {
            arr[i] = Integer.valueOf(sc.next());
        }

        Integer firstDup = null;
        Integer secondDup = null;
        firstloop:
        for (int i = 0; i < arr.length; i++) {
            for (int j = i+1; j < arr.length; j++) {
                if (arr[i].equals(arr[j])) {
                    if (firstDup == null) {
                        firstDup = arr[i];
                    } else {
                        secondDup = arr[i];
                        break firstloop;
                    }
                }
            }
        }

        if (secondDup != null) {
            StringBuilder sb = new StringBuilder(secondDup.toString());
            sb.reverse();
            System.out.println(sb.toString());
        } else {
            if (firstDup != null) {
                System.out.println(firstDup);
            } else {
                System.out.println("No duplicate found");
            }
        }
    }

}