Answer to Question #274484 in Java | JSP | JSF for kkkkkk

Question

The quadrant in which line drawn from the origin resides

is determined by the angle that the line makes with the

positive x axis as follows:

Using this information, write a Java method that accepts the

angle of the line as user input and determines and displays

the quadrant appropriate to the input data. (Note: if the

angle is exactly 0, 90, 180, or 270 degrees the corresponding

line does not reside in any quadrant but lies on an axis).

Note: Use if Control statement

Answer 1

import java.io.*;
import java.util.Scanner;
 class Main{
    static void qua(int angle, int angle2)
    {
        if (angle >0 && angle2 > 0)
            System.out.println("lies in First quadrant");
 
        else if (angle < 0 && angle2 > 0)
            System.out.println("lies in Second quadrant");
 
        else if (angle < 0 && angle2 < 0)
            System.out.println("lies in Third quadrant");
 
        else if (angle > 0 && angle2 < 0)
            System.out.println("lies in Fourth quadrant");
 
        else if (angle == 0 && angle2 > 0)
            System.out.println("lies at positive y axis");
 
        else if (angle == 0 && angle2 < 0)
            System.out.println("lies at negative y axis");
 
        else if (angle2 == 0 && angle < 0)
            System.out.println("lies at negative x axis");
 
        else if (angle2 == 0 && angle > 0)
            System.out.println("lies at positive x axis");
 
        else
            System.out.println("lies at origin");
    }
    public static void main(String[] args)
    {
        Scanner input=new Scanner(System.in);
        int angle = input.nextInt();
        int angle2 = input.nextInt();
        qua(angle, angle2);
    }
}