Answer to Question #272698 in Java | JSP | JSF for harryy

Question

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array/list.

The next lines contain the integers.

The last line contains an integer to be searched.

5
3
21
2
5
23
2

Output

A line containing a string.

Present

Answer 1

SOLUTION CODE

package com.company;

import java.util.*;

class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.print("Enter an integer: ");
        int my_integer = sc.nextInt();
        // Declaring the ArrayList with of integers
        ArrayList<Integer> my_integers_arraylist = new ArrayList<Integer>();
        for (int i = 0; i < my_integer; i++) {
            System.out.print("Enter integer " + (i + 1) + ": ");
            int array_list_integer = sc.nextInt();
            my_integers_arraylist.add(array_list_integer);
        }

        System.out.print("\nEnter an integer to check whether it's present in your arraylist: ");
        int check_integer = sc.nextInt();
        int condition = 0;
        //Now checking
       
        for (int i = 0; i < my_integers_arraylist.size(); i++)
        {
            if(my_integers_arraylist.get(i)==check_integer);
            {
                System.out.println("\nPresent");
                condition = 1;
                break;
            }
        }
        if(condition == 0)
        {
            System.out.println("\nNone");
        }
    }
}

SAMPLE PROGRAM OUTPUT