Answer to Question #272375 in Java | JSP | JSF for harryy

Question

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array/list.

The next lines contain the integers.

The last line contains an integer to be searched.

5
3
21
2
5
23
2

Output

A line containing a string.

Present

Answer 1

import java.io.*;
import java.util.*;
class Main {
    private static void Common(String[] array1,
                                         String[] array2)
    {
        Set<String> set = new HashSet<>();
        for (int i = 0; i < array1.length; i++) {
            for (int j = 0; j < array2.length; j++) {
                if (array1[i] == array2[j]) {
                    set.add(array1[i]);
                    break;
                }
            }
        }
        for (String i : set) {
            System.out.print(i + " ");
        }
    }
    public static void main(String[] args)
    {
        String[] array1
            = { "5", "3", "21", "5", "21","23","2" };
        String[] array2 = { "21", "5", "21" };
        System.out.println("Array 1: "
                           + Arrays.toString(array1));
        System.out.println("Array 2: "
                           + Arrays.toString(array2));
 
        System.out.print("Common Elements: ");
        Common(array1, array2);
        System.out.println("Present");
    }
}