Answer to Question #259151 in Java | JSP | JSF for joy

Question

7. Arraying 102

by CodeChum Admin

We've already made arraying/listing the easy way, but how about arraying/listing and printing the list in reverse order?

Make a program that will input an integer and then using loops, add items on an array/list one by one for the same number of times as that of the first inputted integer. Then, print out the array/list in reverse order, that is, starting from the last item on the array/list down to the first one, each in separated lines.

Input

The first line contains the size of the array/list.

The next lines contains the items of the array/list (integers).

5

1

64

32

2

11

Output

Multiple lines containing integers.

11

2

32

64

1

Answer 1

package arrays;


import java.util.Scanner;




public class Arrays {


    
    public static void main(String[] args) {
        System.out.println("Enter the size of the array: ");
        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        
        int [] arr = new int[n];
        System.out.printf("Enter %d elements of the array: \n",n);
        for(int i=0; i<n; i++){
            arr[i] = scan.nextInt();
        }
        System.out.printf("The %d elements of the array in reverse order are: \n", n);
        int k = n-1;
        for(int i=k; i>=0; i--){
            System.out.printf("Element %d is:   %d\n", (i+1), arr[i]);
        }
        
    }
    
}