Answer to Question #257511 in Java | JSP | JSF for Nikhil Sahoo

Question

In Java, WAP to store name and age of 30 persons in two different arrays. Ask the age range from the use and then display name of those persons who are coming in that age group in descending order of their age. At the end display how many such persons found.

Answer 1

import java.util.Random;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        String[] names = new String[30];
        int[] ages = new int[30];
        Random random = new Random();
        for (int i = 0; i < names.length; i++) {
            names[i] = "Name" + i;
            ages[i] = random.nextInt(100) + 1;
            System.out.println(names[i]+" "+ages[i]);
        }
        System.out.println('\n');
        Scanner in = new Scanner(System.in);
        System.out.println("min:");
        int min = in.nextInt();
        System.out.println("max:");
        int max = in.nextInt();
        int size = 0;
        String[] namesRange = new String[30];
        int[] agesRange = new int[30];
        for (int i = 0; i < ages.length; i++) {
            if (ages[i] >= min && ages[i] <= max) {
                namesRange[size] = names[i];
                agesRange[size++] = ages[i];
            }
        }

        for (int i = 0; i < size; i++) {
            for (int j = i + 1; j < size; j++) {
                if (agesRange[i] < agesRange[j]) {
                    String name = namesRange[i];
                    namesRange[i] = namesRange[j];
                    namesRange[j] = name;
                    int age = agesRange[i];
                    agesRange[i] = agesRange[j];
                    agesRange[j] = age;
                }
            }
        }
        System.out.println("Number of persons: "+size);
        for (int i = 0; i < size; i++) {
            System.out.println(namesRange[i]+" "+agesRange[i]);
        }
    }
}