Answer to Question #249658 in Java | JSP | JSF for Tarurendra Kushwah

Question

Given an array A of N integers and two integers X and Y, find the number of integers in the array that are both less than or equal to X and divisible by Y.

Input

• The first line of the input contains an integer T denoting the number of test cases. The description of each test case follows.
• The first line of each test case contains three space separated integers: N, X and Y.
• The second line contains N space-separated integers A₁, A₂, ..., A_N denoting the array A.

Output

For each test case, output a single line containing the answer.

Constraints

• 1 ≤ T ≤ 10
• 1 ≤ N ≤ 10⁵
• 1 ≤ A₁, A₂, ... ,A_N ≤ 10⁹
• 1 ≤ X, Y ≤ 10⁹

Answer 1

import java.util.Scanner;
public class Main
{
	public static void main(String[] args) {
	    Scanner input=new Scanner(System.in);
	    System.out.println("Enter the three intergers X Y and N respectively: ");
	    int X=input.nextInt();
	    int Y=input.nextInt();
	    int N=input.nextInt();
		int [] A = new int [5];
		System.out.print("Enter the elements of the array: ");
	    A[0] =input.nextInt();
	    A[1]=input.nextInt();
	    A[2]=input.nextInt();
	    A[3]=input.nextInt();
	    A[4]=input.nextInt();
        System.out.println("The numbers of the array divisible by Y and less than or equal to X are: ");
		if(A[0]%Y==0 && A[0]<=X){
		    System.out.println(A[0]);}
		 if(A[1]%Y==0 && A[1]<=X){
		    System.out.println(A[1]);}
		 if(A[2]%Y==0 && A[2]<=X){
		    System.out.println(A[2]);}
		 if(A[3]%Y==0 && A[3]<=X){
		    System.out.println(A[3]);}
		 if(A[4]%Y==0 && A[4]<=X){
		    System.out.println(A[4]);}
	}
}