Answer to Question #169159 in Java | JSP | JSF for Chandra sena reddy

Question #169159

Square at Alternate Indices

Given an array

myArray of numbers, write a function to square the alternate numbers of the myArray, starting from index 0 using the array method map.Input

The input will be a single line containing an array myArray

Output

The output should be a single line containing an array with alternate numbers squared

Constraints

Each value in the array must be a number

Sample Input 1

[ 1, 2, 3, 4, 5 ]

Sample Output 1

[ 1, 2, 9, 4, 25 ]

Sample Input 2

[ 2, 4 ]

Sample Output 2

[ 4, 4 ]

and the given code to fill the function is :

"use strict";

process.stdin.resume();

process.stdin.setEncoding("utf-8");

let inputString = "";

let currentLine = 0;

process.stdin.on("data", (inputStdin) => {

inputString += inputStdin;

});

process.stdin.on("end", (_) => {

inputString = inputString.trim().split("\n").map((str) => str.trim());

main();

});

function readLine() {

return inputString[currentLine++];

}

/* Please do not modify anything above this line */

function main() {

const myArray = JSON.parse(readLine());

/* fill the code in this function */

}

Expert's answer

<!DOCTYPE html>
<html>
<body>

<h2>The required result are given below</h2>

<p>The value of array which is at odd place will get in square.</p>

<p id="demo"></p>

<script>
var x = [ 2, 4 ];
var arr=" ";

var i;
for(i = 0;i< x.length; i++){

    if(i%2==0){
    arr +=x[i]*x[i]+",";
    }else{
    arr +=x[i]+","
    }
}
document.getElementById("demo").innerHTML ="The value of array is: " + arr;
</script>

</body>
</html>

Answer to Question #169159 in Java | JSP | JSF for Chandra sena reddy

myArray of numbers, write a function to square the alternate numbers of the myArray, starting from index 0 using the array method map.Input

Output

Constraints

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