Answer to Question #303261 in HTML/JavaScript Web Application for king

Question

find the first value

given an array myArray of positive integers, write a JS program to find the first smallest integer divisible 2 and 3 Log the number or Undefined.in case no integer is found divisible by 2 and 3

input1

[51,18,15,12]

output1

[12]

input2

[41,29,17,19,31]

output2

undefined

"use strict";

process.stdin.resume();

process.stdin.setEncoding("utf-8");

let inputString = "";

let currentLine = 0;

process.stdin.on("data", (inputStdin) => {

 inputString += inputStdin;

});

process.stdin.on("end", (_) => {

 inputString = inputString

  .trim()

  .split("\n")

  .map((str) => str.trim());

 main();

});

function readLine() {

 return inputString[currentLine++];

}

function main() {

 let myArray = JSON.parse(readLine());

 /* Please do not modify anything above this line */

 /* Write your code here and log the output */

}

Answer 1

"use strict";

process.stdin.resume();
process.stdin.setEncoding("utf-8");

let inputString = "";
let currentLine = 0;

process.stdin.on("data", (inputStdin) => {
    inputString += inputStdin;
});

process.stdin.on("end", (_) => {
    inputString = inputString
    .trim()
    .split("\n")
    .map((str) => str.trim());
    main();
});

function readLine() {
    return inputString[currentLine++];
}

function main() {
    let myArray = JSON.parse(readLine());

    /* Please do not modify anything above this line */

    /* Write your code here and log the output */
    let min = myArray[0], result = undefined, index = 0;
    while (myArray.length) {
        myArray.map((e, i)=> {
            if (e < min) min = e;
            index = i
        })
        if (min % 3 === 0 && min % 2 === 0) {
            result = min;
            break
        }
        myArray.splice(index, 1);
        min = myArray[0];
    }

    console.log(result)
}