Consider the following relation with set of functional dependencies R(ABCDEF) ABC->D, ABD->E, CD->F, CDF->B, BF->D a) Identify the candidate key(s) in the relation (with proper steps followed). b) Identify which normal form this relation is in and reason for the answer
On the right hand side of each relation, A and C are absent. Therefore the candidate key comprises of A and C. We find the closure of AC and check the different combinations of AC.
Hence ABC, ABF are candidate keys
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