Answer to Question #263371 in Databases | SQL | Oracle | MS Access for Ravi kumar pandey

Question

.Consider a schedule with 3 transactions with 2, 3, and 4 operations respectively. Calculate the possible

number of

c) Serial schedules

d) Non serial schedules

Answer 1

= (1 + 2 + 3)! / (1! + 2! + 3!) = 6! / 9 = 120

Number of Serial Schedules,
= 3! = 6
Number of Non-Serial Schedules,
= Total Number of Schedules - Number of Serial Schedules 
= 120 - 6 
= 114