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Make a C++ program that will input a number and display the sum of the numbers from 1 to the input number using do while loop.
Each student would have to output the assigned Character using Java or C++ and make it rotate in 360 degrees clockwise
How to execute this using vector
#include <iostream>
bool doesexists(int array[], int toseaarch, int size);
const short int SIZE = 10;
int main() {
int myarray[SIZE], distinct_ctr = 0, index = 0;
std::cout << "Enter 10 numbers: ";
for (index = 0; index < SIZE; index++) {
int tmp;
std::cin >> tmp;
if (!doesexists(myarray, tmp, SIZE)) {
myarray[distinct_ctr] = tmp;
distinct_ctr++;
}
}
std::cout << "distinct numbers are: ";
for (index = 0; index < distinct_ctr; index++)
std::cout << myarray[index] << " ";
std::cout << "\n";
return 0;
}
bool doesexists(int array[], int toseaarch, int size) {
for (int index = 0; index < size; index++) {
if (toseaarch == array[index])
return true;
}
return false;
}
write a program that calculates and prints the monthly paycheck for an employee. The net pay is calculated after taking the following deductions:
Federal Income Tax: 15%
State Tax: 3.5%
Social Security Tax: 5.75%
Medicare/Medicaid Tax: 2.75%
Pension Plan: 5%
Health Insurance: $75.00
Simplify the following functions using a K-map
a. F(X, Y) = m2 + m3
b. F(X, Y) = X + X’Y
c. F(X, Y) = X’ + XY’
d. F(X, Y, Z) = m0 + m2 + m5 + m7
e. F(X, Y,Z) = X’Y’Z’ + X’YZ + XY’Z + XYZ
f. F(X,Y, Z) = π ( 0, 2, 5,7)
g. F(X, Y, Z) = XY’Z + X’ + Z + Y’Z’
h. F(W, X, Y, Z) = X’ Y’Z’ + XYZ’ + WXY + W’X’Y’ + WZ
i. F(W, X, Y, Z) = X’ + XZ’ + WX’Y + W’Y’ + WZ
- write an application to print out the numbers 10 through 49 in the following manner
10 11 12 13 14 15 16 17 18 19
20 21 22 23 24 25 26 27 28 29
30 31 32 33 34 35 36 37 38 39
40 41 42 43 44 45 46 47 48 49
Input Combination
by CodeChum Admin
We’ve tried adding together integers, so how about adding characters as well? Well we really don't know how to create a variable that holds the combined characters (at least for now) so let's just print them together in 1 string instead.
Instructions:
Input two characters in one line, separated by a space.
Make the strings be printed out like it’s concatenated (or combined) by printing it without spaces in between. Refer to the sample output for your reference.
Input
A line containing two characters separated by a space.
A·B
Output
A line containing two characters.
AB
Integer Pairing
by CodeChum Admin
Now this one's a tad bit tricky, but you can definitely do it!
Instructions:
Input five integers in one line, with each integer separated by a space.
Add the 1st and 2nd integers together and store the sum inside a variable.
Add the 3rd and 4th integers together and store the sum inside a variable.
Multiply the two sums and raise the product result to the power of the 5th integer.
Print out the result.
Input
A line containing five integers separated by a space.
1·2·3·4·5
Output
A line containing an integer.
4084101
How to execute this using vector
#include <cmath>
#include <iostream>
const short int SIZE = 10;
double mean(const double x[], int size);
// Compute the deviation of double values
double deviation(const double x[], int size);
int main() {
double myarray[SIZE];
std::cout << "Enter the number: ";
for (int index = 0; index < SIZE; index++)
std::cin >> myarray[index];
std::cout << "The mean is " << mean(myarray, SIZE) << ".\n";
std::cout << "The standard deviation is " << deviation(myarray, SIZE)
<< ".\n";
return 0;
}
double mean(const double x[], int size) {
double total = 0;
for (int index = 0; index < size; index++)
total += x[index];
return total / size;
}
double deviation(const double x[], int size) {
double themean = mean(x, size);
double total = 0;
for (int index = 0; index < size; index++) {
total += pow(x[index] - themean, 2);
}
return sqrt(total / size - 1);
}
How to execute this using vector
#include <cstdlib>
#include <ctime>
#include <iostream>
int main() {
int dice[6] = {0};
srand(time(0));
for (int ctr = 0; ctr < 10000; ctr++) {
switch ((rand() % 6) + 1) {
case 1:
dice[0] += 1;
break;
case 2:
dice[1] += 1;
break;
case 3:
dice[2] += 1;
break;
case 4:
dice[3] += 1;
break;
case 5:
dice[4] += 1;
break;
case 6:
dice[5] += 1;
break;
}
}
for (int index = 0; index < 6; index++)
std::cout << index + 1 << " appears " << dice[index] << " time/s\n";
return 0;
}
