Answer to Question #7652 in C++ for zane

Question

int display(char ch, int n);

that displays the character ch on the stdout device (screen) consecutively n times if n>0 and displays nothings if n≤0. When n>0 and ch is not the blank character, the function will also display an additional newline at the end. The function display returns the actual number of characters (excluding the possible newline at the end) displayed.

Write a driver program, making use of the above specified function display, that line by line repeatedly display the character pattern

*
**
***
****
*****
******
*******
********
*********
**********
++++++++++
+++++++++
++++++++
+++++++
++++++
+++++
++++
+++
++
+

until a given numer of non-whitespace characters are displayed. In other words, the program will first ask the user to enter the total number, say target, of non-whitespace characters to be displayed, and then it will repeatedly display the above pattern until exactly target non-whitespac

Answer 1

#include <iostream>
using namespace std;

int display(char ch, int n);

int main() {
char ch;
int n;
cout << "Enter character: ";
cin >> ch;
cout << " Enter number: ";
cin >> n;
int number = display(ch, n);
cout << endl << number << endl;
return 0;
}

int display(char ch, int n) {
int k = 0;
for (int i = 1; i <= n; i++) {
& for (int j = 1; j <= i; j++)
& cout << ((j > 1) ? " " : "");
& for (int j = 1; j <= i; j++)
& cout << ch;
& cout << endl;
& k += i;
}
ch++;
for (int i = n; i >0; i--) {
& for (int j = i ; j > 0; j--)
& cout << ((j > 1) ? " " : "");
& for (int j = i ; j > 0; j--)
& cout << ch;
& cout << endl;
}
return k;
}