Question

Write a programe that inputs an integer between 1 and 10 and use a switch statement to determine odd no. And the no. Which are a multiple of 4, otherwise the switch statement should inform the user that the entered no. Is neither even nor multiple of 4.
The programe should be repeated until the user enters -1, use a do while statement for repeat part

Answer 1

#include<iostream>using namespace std;int main(){   bool b = true;   int x;   do   {      cout << "Enter number from 1 to 10 (for EXIT type -1):";      cin >> x;      switch(x)      {      case -1:         b = false;         break;      case 1:         cout << "Neither even, nor multiple of 4\n";         cout << "\n";         break;               case 2:         cout << "Even, but not a multiple of 4\n";         cout << "\n";         break;               case 3:         cout << "Even, but not a multiple of 4\n";            cout << "\n";         break;               case 4:         cout << "Not even, but a multiple of 4\n";            cout << "\n";         break;               case 5:         cout << "Even, but not a multiple of 4\n";            cout << "\n";         break;               case 6:         cout << "Neither even, nor multiple of 4\n";            cout << "\n";         break;                  case 7:         cout << "Even, but not a multiple of 4\n";         cout << "\n";         break;               case 8:         cout << "Not even, but a multiple of 4\n";         cout << "\n";         break;               case 9:         cout << "Neither even, nor multiple of 4\n";         cout << "\n";         break;               case 10:         cout << "Neither even, nor multiple of 4\n";            cout << "\n";         break;               default:            cout << "Please enter number from 1 to 10!\n";            cout << "\n";            break;            }   }while(b);   return 0;}