Answer to Question #37187 in C++ for aisha

Question

Write a program to solve the following equation
Y=1/2!-2/3!+3/4!-4/5!+….n/(n+1)!
Where n is entered by the user. For example if user enters 3 then your program should calculate Y as 1/2!-2/3!+3/4!

Answer 1

#include <iostream>

using namespace std;

int main(int argc, char const *argv []) 

{    
   int     n,            
          fact    = 1;
   double  out     = 0;
    cout << "Input n: "; cin >> n;
    for(int i = 1, j = 2; i <= n; i++, j++)    
{        
    double temp = i;
        fact *= j;        
        temp /= fact;
        if (i%2 == 0)            
             out -= temp;        
        else            
             out += temp;    
 }
    cout << "Result: " << out << endl;
    return 0; 
}