Answer to Question #350400 in C++ for kristine

Question

Write a C++ function that determines in which quadrant a line

drawn from the origin resides. The determination of the quadrant

is made using the angle that the line makes with the positive x

axis as follows:

Note: if the angle is exactly 0,90,180,270 degrees the

corresponding line does not reside in any quadrant but lies on an

axis.

Angle from the

positive x axis Quadrant

Between 0 and 90 degrees =1

Between 90 and 180 degrees =2

Between 180 and 270 degrees =3

Between 270 and 360 degrees = 4

Answer 1

#include <iostream>
using namespace std;

int main(void) {
    
    int angle, quadrant = 0;
    
    cout<<"angle: ";
    cin>>angle;
    if(angle>=360)
        angle = angle%360;

    if(angle>0 && angle<90)
        quadrant = 1;
    else if(angle>90 && angle<180)
        quadrant = 2;
    else if(angle>180 && angle<270)
        quadrant = 3;
    else if(angle>270 && angle<360)
        quadrant = 3;    
    else if(angle==0||angle==180)
        cout<<"The line does not reside in any quadrant but lies on an axis X"<<endl;    
    else if(angle==90||angle==270)
        cout<<"The line does not reside in any quadrant but lies on an axis Y"<<endl;            
     if(quadrant!=0)
        cout<<"quadrant: "<<quadrant<<endl;
    
  return 0;
}