Answer to Question #346150 in C++ for Zee

Question

Write a program that dynamically allocates an array large enough to hold a user-defined number of test

scores. Once all the scores are entered, the array should be passed to a function that sorts them in

ascending order. Another function should be called that calculates the average score. The program

should display the sorted list of scores and averages with appropriate headings. Use pointer notation

rather than array notation whenever possible.

Input Validation: Do not accept negative numbers for test scores.

Example

Enter the number of test scores: 4

Enter each test score:

Test#1: 34

Test #2: 73

Test #3: 22

Test #4: 89

Sorted test scores:

Test #1: 22

Test #2: 34

Test #3: 73

Test #4: 89

Average = 54.5

Answer 1

#include <iostream>
void sort(int* array, int count)
{
	int i, j, temp;
	for (i = 0; i < count - 1; i++)
		for (j = 0; j < count - 1 - i; j++)
			if (*(array + j) > *(array + j + 1))
			{
				temp = *(array + j + 1);
				*(array + j + 1) = *(array + j);
				*(array + j) = temp;
			}
}
float average(int* array, int count)
{
	int i;
	float result = 0;
	for (i = 0; i < count; i++)
		result = result + *(array + i);
	return result / count;
}
int main()
{
	int* array; int i; int count = -1; int value = -1;
	float averagescore;
	while (count <= 0)
	{
		std::cout << "Enter the number of test scores: ";
		std::cin >> count;
	}
	array = new int[count];
	std::cout << "Enter each test score: \n";
	for (i = 0; i < count; i++)
	{
		while (value <= 0)
		{
			std::cout << "Test #" << i + 1 << ": ";
			std::cin >> value;
		}
		*(array + i) = value;
		value = -1;
	}
	sort(array, count);
	std::cout << "Sorted test scores: \n";
	for (i = 0; i < count; i++)
		std::cout << "Test #" << i + 1 << ": " << *(array + i) << "\n";
	averagescore = average(array, count);
	std::cout << "Average = " << averagescore;
}