Answer to Question #340626 in C++ for Codechum 1

Question

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array.

The next lines contain the integers.

The last line contains an integer to be searched.

5

3

21

2

5

23

2

Output

A line containing a string.

Present

Answer 1

#include <iostream>

using namespace std;

int main() {
	int size, num;
	cin >> size;
	int* arr = new int[size];
	for (int i = 0; i < size; ++i) {
		cin >> arr[i];
	}
	cin >> num;
	bool present = false;
	for (int i = 0; i < size; ++i) {
		if (num == arr[i]) {
			present = true;
			break;
		}
	}
	if (present) cout << "Present";
	else cout << "None";
	return 0;
}