Answer to Question #334615 in C++ for Jack

Question

a. Write a function convert() that converts a decimal number to a binary, octal, and

hexadecimal equivalents. The function will take two arguments: first argument will be

the number to be converted and second argument will be the base in which this number

is to be converted. Function should return the converted value. You may use strings to

represent converted numbers like “0x3A”, “00101100”, “72” etc. Lower limit must be smaller than upper limit.

b. Call convert() function in the main program to produce the following output.

Example output:

Enter upper limit = 20

Enter lower limit = 10

Decimal Binary Octal Hexadecimal

10 00001010 12 0xA

11 00001011 13 0xB

12 00001100 14 oxC

13 00001101 15 0xD

14 00001110 16 0xE

15 00001111 17 0xF

16 00010000 20 0x10

17 00010001 21 0x11

18 00010010 22 0x12

19 00010011 23 0x13

20 00010100 24 0x14

Answer 1

#include <bits/stdc++.h>
#include <iostream>
using namespace std;
 
int decToBinary(int n)
{
    for (int i = 8; i >= 0; i--) {
        int k = n >> i;
        if (k & 1)
            cout << "1";
        else
            cout << "0";
    }
    cout << "\t";
}


string intToOctal(int n)
{
    stringstream st;
    st << oct << n;
    return st.str();
}


void decToHexa(int n) 
{ 
    char hexaDeciNum[100];
    int i = 0;
    while (n != 0) {
        int temp = 0;
        temp = n % 16;
        if (temp < 10) {
            hexaDeciNum[i] = temp + 48;
            i++;
        }
        else {
            hexaDeciNum[i] = temp + 55;
            i++;
        }
        n = n / 16;
    }
    for (int j = i - 1; j >= 0; j--)
        cout << hexaDeciNum[j]; 
}


void convert(int i){
    cout << i << "\t";
    decToBinary(i);
    cout << intToOctal(i) << "\t" << "0x";
    decToHexa(i);
    cout << "\n";
}
 
int main()
{  
    int upper, lower;
    cout << "Enter upper limit = ";
    cin >> upper;
    cout << "Enter lower limit = ";
    cin >> lower;
    if (upper > lower){
        for (int i = lower; i <= upper; i++) {
            convert(i);
        }
    }
    else{
        cout << "You enter incorrect number. Try again.";
    }
    
    
    return 0;
}