Answer to Question #333748 in C++ for jane

Question

Write a C++ program in which write a function convert() that converts a decimal number to a binary, octal, and

hexadecimal equivalents. The function will take two arguments: first argument will be

the number to be converted and second argument will be the base in which this number

is to be converted. Function should return the converted value. You may use strings to

represent converted numbers like “0x3A”, “00101100”, “72” etc.

b. Call convert() function in the main program to produce the following output. It is same

as you made in the previous assignment.

Example output:

Enter upper limit = 20

Enter lower limit = 30

Please enter a value of lower limit between 0 and the upper limit and try again.

Enter lower limit again = 10

............................................................................

Decimal Binary Octal Hexadecimal

Answer 1

#include<iostream>
#include<string>


using namespace std;


int ToBin(int n)
{
	int binary = 0;
	int rem, prod = 1;
	for (;;) 
	{
		if (n == 0)break;
		rem = n % 2;
		binary = binary + (rem*prod);
		n = n / 2;
		prod *= 10;
	}
	return binary;
}


int ToOctal(int n)
{
	int octal = 0;
	int rem, prod = 1;
	while (n != 0)
	{
		rem = n % 8;
		octal = octal + (rem*prod);
		n = n / 8;
		prod *= 10;
	}
	return octal;
}


string ToHex(int n)
{
	string hexal="";
	do
	{
		int temp = n % 16;
		if (temp < 10)
			hexal=char(temp+48)+hexal;
		else
		{
			hexal = char(temp + 55) + hexal;
		}
		n = n / 16;
	} while (n != 0);
	return hexal;
}


int main()
{
	int lowLim, upLim;
	do
	{
		cout << "Please, enter lower limit and upper limit: ";
		cin >> lowLim >> upLim;
		if (lowLim >= 0 && lowLim < upLim)
		{
			cout << "Bin\tOct\tHex\n";
			for (int i = lowLim; i <= upLim; i++)
			{
				cout << ToBin(i)<<"\t" <<ToOctal(i)<<"\t"<<ToHex(i)<< endl;
			}
		}
		else
			cout << "Incorrect input!"<<endl;
	} while (lowLim <= 0 || lowLim >= upLim);
}