Assuming that there are 7.481 gallons in a cubic foot, write a program that asks the user to enter the number of gallons and display the equivalent in cubic feet.
#include #include using namespace std;
int main()
{
double gallons;
cout << "Please enter the number of gallons: ";
cin >> gallons;
if (cin.fail()) {
cout << "Invalid number of gallons." << endl;
return 1;
}
double cubic_feet = gallons / 7.481;
cout << "The number of cubic feet is " << setprecision(3) << cubic_feet <<
endl;
return 0;
}