Answer to Question #325782 in C++ for rahul

Question

Write a program to overload operators in the same program by writing suitable operator member

functions for following expression:

O7= ((O1 % O2)>(O3 || O4) - (O5>O6)) [Here O1,O2,O3,O4,O5,O6 and O7 are objects of a class

“overloading”, and this class is having one integer data member]

Answer 1

#include <iostream>


class Overloading {
  private:
    int value;
  public:
    Overloading(int val = 0) : value(val) {}
    // Although type of expression (O1 % O2) > (O3 || O4) - (O5 > O6) is boolean,
    // it will be automatically converted to integer (true -> 1, false -> 0),
    // then passed into constructor to create temporary object,
    // then following assignment operator will be called with created object


    // Here is returning reference (Overloading& instead of simply Overloading)
    // because we don't want to create unnecessary copy of object
    Overloading& operator =(const Overloading& right) {
      value = right.value;
      return *this;
    }
    Overloading operator %(const Overloading& right) {
      return Overloading(value % right.value);
    }
    bool operator >(const Overloading& right) {
      return value > right.value;
    }
    bool operator ||(const Overloading& right) {
      return value || right.value;
    }
    // Here is passing a constant reference; reference, again, to make not
    // an extra copy, and constant to make possible using of temporary objects
    // as in expression (o[2] || o[3]) - (o[4] > o[5]), where (o[4] > o[5])
    // is a temporary value that c++ forbids converting to a non-constant reference
    Overloading operator -(const Overloading& right) {
      return Overloading(value - right.value);
    }
    // Opearators for handy input and output Overloading objects
    friend std::istream& operator >>(std::istream& is, Overloading& o) {
      is >> o.value;
      return is;
    }
    friend std::ostream& operator <<(std::ostream& os, const Overloading& o) {
      os << o.value;
      return os;
    }
    ~Overloading() {}
};


int main() {
  Overloading o[6];
  std::cout << "Enter 6 integers separated by space: ";
  for (int i = 0; i < 6; ++i) {
    std::cin >> o[i];
  }
  Overloading result;
  result = (o[0] % o[1]) > (o[2] || o[3]) - (o[4] > o[5]);
  std::cout << "Result of (O1 % O2) > (O3 || O4) - (O5 > O6) is " << result << '\n';
  return 0;
}