Question

1. Create a 'for' loop that will display numbers: 100 90 80 70 60

2. Create a 'for' loop that will display all EVEN numbers from 1 to N. (N is a positive number entered by the user.)

3. Create a 'while' loop that will accept numbers but stops when it encounters a negative number.

Answer 1

#include <iostream>
using namespace std;
 
int main() {
    int i,n;
// 1.
 for (i=100; i>=60; i=i-10){
     cout<<i<<"  ";
 }
 
 // 2.
 cout<<"\n\nEnter N: ";
 cin>>n;
 for (i=1; i<=n; i++){
     if(i%2==0)
     cout<<i<<"  ";
 }

// 3.
cout<<endl<<endl;
 while(n>0){
     cout<<"Enter N: ";
     cin >>n;
 }
 
  return 0;
}